-32x=12x-2x+2x^2

Solution for -32x=12x-2x+2x^2 equation:

-32x=12x-2x+2x^2

We move all terms to the left:

-32x-(12x-2x+2x^2)=0

We get rid of parentheses

-2x^2-12x+2x-32x=0

We add all the numbers together, and all the variables

-2x^2-42x=0

a = -2; b = -42; c = 0;
Δ = b2-4ac
Δ = -422-4·(-2)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-42}{2*-2}=\frac{0}{-4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+42}{2*-2}=\frac{84}{-4}
=-21
$